تاریخچه ی:
جدول انتگرال توابع لگاریتمی
تفاوت با نگارش: 2
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| ^@#16: | | ^@#16: |
| !جدول انتگرال توابع لگاریتمی: | | !جدول انتگرال توابع لگاریتمی: |
| @@{TEX()} {\int e^x\,dx = e^x + C} {TEX}@@ | | @@{TEX()} {\int e^x\,dx = e^x + C} {TEX}@@ |
| @@{TEX()} {\int a^x\,dx = \frac{a^x}{\ln{a}} + C} {TEX}@@ | | @@{TEX()} {\int a^x\,dx = \frac{a^x}{\ln{a}} + C} {TEX}@@ |
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| @@{TEX()} {\int\ln cx\,dx = x\ln cx - \frac{x}{c}} {TEX}@@ | | @@{TEX()} {\int\ln cx\,dx = x\ln cx - \frac{x}{c}} {TEX}@@ |
| @@{TEX()} {\int (\ln x)^2\; dx = x(\ln x)^2 - 2x\ln x + 2x} {TEX}@@ | | @@{TEX()} {\int (\ln x)^2\; dx = x(\ln x)^2 - 2x\ln x + 2x} {TEX}@@ |
| @@{TEX()} {\int (\ln cx)^n\; dx = x(\ln cx)^n - n\int (\ln cx)^{n-1} dx} {TEX}@@ | | @@{TEX()} {\int (\ln cx)^n\; dx = x(\ln cx)^n - n\int (\ln cx)^{n-1} dx} {TEX}@@ |
| @@{TEX()} {\int \frac{dx}{\ln x} = \ln|\ln x| + \ln x + \sum^\infty_{i=2}\frac{(\ln x)^i}{i\cdot i!}} {TEX}@@ | | @@{TEX()} {\int \frac{dx}{\ln x} = \ln|\ln x| + \ln x + \sum^\infty_{i=2}\frac{(\ln x)^i}{i\cdot i!}} {TEX}@@ |
| @@{TEX()} {\int \frac{dx}{(\ln x)^n} = -\frac{x}{(n-1)(\ln x)^{n-1}} + \frac{1}{n-1}\int\frac{dx}{(\ln x)^{n-1}} \qquad\mbox{( }n\neq 1\mbox{)}} {TEX}@@ | | @@{TEX()} {\int \frac{dx}{(\ln x)^n} = -\frac{x}{(n-1)(\ln x)^{n-1}} + \frac{1}{n-1}\int\frac{dx}{(\ln x)^{n-1}} \qquad\mbox{( }n\neq 1\mbox{)}} {TEX}@@ |
| @@{TEX()} {\int x^m\ln x\;dx = x^{m+1}\left(\frac{\ln x}{m+1}-\frac{1}{(m+1)^2}\right) \qquad\mbox{( }m\neq -1\mbox{)}} {TEX}@@ | | @@{TEX()} {\int x^m\ln x\;dx = x^{m+1}\left(\frac{\ln x}{m+1}-\frac{1}{(m+1)^2}\right) \qquad\mbox{( }m\neq -1\mbox{)}} {TEX}@@ |
| @@{TEX()} {\int x^m (\ln x)^n\; dx = \frac{x^{m+1}(\ln x)^n}{m+1} - \frac{n}{m+1}\int x^m (\ln x)^{n-1} dx \qquad\mbox{( }m\neq -1\mbox{)}} {TEX}@@ | | @@{TEX()} {\int x^m (\ln x)^n\; dx = \frac{x^{m+1}(\ln x)^n}{m+1} - \frac{n}{m+1}\int x^m (\ln x)^{n-1} dx \qquad\mbox{( }m\neq -1\mbox{)}} {TEX}@@ |
| @@{TEX()} {\int \frac{(\ln x)^n\; dx}{x} = \frac{(\ln x)^{n+1}}{n+1} \qquad\mbox{( }n\neq -1\mbox{)}} {TEX}@@ | | @@{TEX()} {\int \frac{(\ln x)^n\; dx}{x} = \frac{(\ln x)^{n+1}}{n+1} \qquad\mbox{( }n\neq -1\mbox{)}} {TEX}@@ |
| @@{TEX()} {\int \frac{\ln x\,dx}{x^m} = -\frac{\ln x}{(m-1)x^{m-1}}-\frac{1}{(m-1)^2 x^{m-1}} \qquad\mbox{( }m\neq 1\mbox{)}} {TEX}@@ | | @@{TEX()} {\int \frac{\ln x\,dx}{x^m} = -\frac{\ln x}{(m-1)x^{m-1}}-\frac{1}{(m-1)^2 x^{m-1}} \qquad\mbox{( }m\neq 1\mbox{)}} {TEX}@@ |
| @@{TEX()} {\int \frac{(\ln x)^n\; dx}{x^m} = -\frac{(\ln x)^n}{(m-1)x^{m-1}} + \frac{n}{m-1}\int\frac{(\ln x)^{n-1} dx}{x^m} \qquad\mbox{( }m\neq 1\mbox{)}} {TEX}@@ | | @@{TEX()} {\int \frac{(\ln x)^n\; dx}{x^m} = -\frac{(\ln x)^n}{(m-1)x^{m-1}} + \frac{n}{m-1}\int\frac{(\ln x)^{n-1} dx}{x^m} \qquad\mbox{( }m\neq 1\mbox{)}} {TEX}@@ |
| @@{TEX()} {\int \frac{x^m\; dx}{(\ln x)^n} = -\frac{x^{m+1}}{(n-1)(\ln x)^{n-1}} + \frac{m+1}{n-1}\int\frac{x^m dx}{(\ln x)^{n-1}} \qquad\mbox{( }n\neq 1\mbox{)}} {TEX}@@ | | @@{TEX()} {\int \frac{x^m\; dx}{(\ln x)^n} = -\frac{x^{m+1}}{(n-1)(\ln x)^{n-1}} + \frac{m+1}{n-1}\int\frac{x^m dx}{(\ln x)^{n-1}} \qquad\mbox{( }n\neq 1\mbox{)}} {TEX}@@ |
| @@{TEX()} {\int \frac{dx}{x\ln x} = \ln|\ln x|} {TEX}@@ | | @@{TEX()} {\int \frac{dx}{x\ln x} = \ln|\ln x|} {TEX}@@ |
| @@{TEX()} {\int \frac{dx}{x^n\ln x} = \ln|\ln x| + \sum^\infty_{i=1} (-1)^i\frac{(n-1)^i(\ln x)^i}{i\cdot i!}} {TEX}@@ | | @@{TEX()} {\int \frac{dx}{x^n\ln x} = \ln|\ln x| + \sum^\infty_{i=1} (-1)^i\frac{(n-1)^i(\ln x)^i}{i\cdot i!}} {TEX}@@ |
| @@{TEX()} {\int \frac{dx}{x (\ln x)^n} = -\frac{1}{(n-1)(\ln x)^{n-1}} \qquad\mbox{( }n\neq 1\mbox{)}} {TEX}@@ | | @@{TEX()} {\int \frac{dx}{x (\ln x)^n} = -\frac{1}{(n-1)(\ln x)^{n-1}} \qquad\mbox{( }n\neq 1\mbox{)}} {TEX}@@ |
| @@{TEX()} {\int \sin (\ln x)\;dx = \frac{x}{2}(\sin (\ln x) - \cos (\ln x))} {TEX}@@ | | @@{TEX()} {\int \sin (\ln x)\;dx = \frac{x}{2}(\sin (\ln x) - \cos (\ln x))} {TEX}@@ |
| @@{TEX()} {\int \cos (\ln x)\;dx = \frac{x}{2}(\sin (\ln x) + \cos (\ln x))} {TEX}@@ | | @@{TEX()} {\int \cos (\ln x)\;dx = \frac{x}{2}(\sin (\ln x) + \cos (\ln x))} {TEX}@@ |
| @@{TEX()} {\int e^x (x \ln x - x - \frac{1}{x})\;dx = e^x (x \ln x - x - \ln x)} {TEX}@@ | | @@{TEX()} {\int e^x (x \ln x - x - \frac{1}{x})\;dx = e^x (x \ln x - x - \ln x)} {TEX}@@ |
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| !همچنین ببینید: | | !همچنین ببینید: |
| *((جدول انتگرال توابع گویا)) | | *((جدول انتگرال توابع گویا)) |
| *((جدول انتگرال توابع گنگ)) | | *((جدول انتگرال توابع گنگ)) |
| *((جدول انتگرال توابع نمایی)) | | *((جدول انتگرال توابع نمایی)) |
| *((جدول انتگرال توابع مثلثاتی)) | | *((جدول انتگرال توابع مثلثاتی)) |
| + | *((جدول انتگرال معکوس توابع مثلثاتی)) |
| *((جدول انتگرال توابع هیپربولیک)) | | *((جدول انتگرال توابع هیپربولیک)) |
| #@^ | | #@^ |